الزمن النجمي

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positional

الزمن النجمي

Which stars are on your local meridian? It depends on the time at which you observe. In fact, it depends on both the date and the (clock) time,because the Earth is in orbit around the Sun.

Consider the Earth at position E1 on the diagram. The star shown is on the meridian at midnight by the clock. But three months later, when the Earth reaches position E2 , the same star is on the meridian at 6 p.m. by the clock.

Our clocks are set to run (approximately) on solar time (sun time). But for astronomical observations, we need to use sidereal time (star time).

Consider the rotation of the Earth relative to the stars. We define one rotation of Earth as one sidereal daymeasured as the time between two successive meridian passages of the same star. Because of the Earth's orbital motion, this is a little shorter than a solar day. (In one year, the Earth rotates 365 times relative to the Sun, but 366 times relative to the stars. So the sidereal day is about 4 minutes shorter than the solar day.)

We define Local Sidereal Time (LST) to be 0 hours, when the vernal equinox is on the observer's local meridian. One hour later, the local Hour Angle (LHA) of the equinox is +1h (by the definition of Hour Angle), and the Local Sidereal Time is 1h. So at any instant,

Local Sidereal Time = Local Hour Angle of the vernal equinox.

Here's an alternative definition: suppose that LST = 1h. This means that the vernal equinox has moved 15° (1h) west of the meridian, and now some other star X is on the meridian. But the Right Ascension of star X is the angular distance from the vernal equinox to X = 1h = LST. So at any instant,

Local Sidereal Time = Right Ascension of whichever stars are on the meridian.

And in general,

the Local Hour Angle of a star = Local Sidereal Time - RA of the star.

However, at any instant, different observers, to the east or west, will have different stars on their local meridians. We need to choose one particular meridian to act as a reference point; we choose Greenwich.

We define the Greenwich Hour Angle of X as the Hour Angle of X relative to the celestial meridian at Greenwich. Then we can define Greenwich Sidereal Time (GST) as the Greenwich Hour Angle of the vernal equinox. This gives the important relation

LST = GST - longitude west

.

Recall that the Local Hour Angle (LHA) of a star = Local Sidereal Time - RA of the star. In particular, the Greenwich Hour Angle (GHA) of a star = Greenwich Sidereal Time - RA of the star.
Combining these, we find

LHA(star) = GHA(star) - longitude west

.

تمرين:

At midnight on 1998 February 4th, Local Sidereal Time at St.Andrews was 8h45m. St.Andrews has longitude 2°48'W. What was the Local Hour Angle of Betelgeuse (R.A. = 5h55m) at midnight?

At what time was Betelgeuse on the meridian at St.Andrews?

At what time was Betelgeuse on the meridian at Greenwich?

الحل:

RA of Betelgeuse = 5h 55m At midnight, LST = 8h 45m

Local Hour Angle = LST - RA

so the Local Hour Angle of Betelgeuse was :

8h 45m - 5h 55m = 2h 50m.

At what time was Betelgeuse on the meridian at St.Andrews?

On the meridian, Local Hour Angle = 0, so if Betelgeuse was on the meridian at St.Andrews,

LST in St.Andrews = RA of Betelgeuse = 5h 55m. (Recall that LST = RA of stars on local meridian.)

We are told that the LST was 8h 45m at midnight. But at midnight, Betelgeuse was at Hour Angle 2h50m, so it would be on the meridian 2h 50m before midnight, that is, at 21h 10m. So Betelgeuse was on the meridian in St.Andrews at 21h 10m.

At what time was Betelgeuse on the meridian at Greenwich?

St.Andrews is 2°48' west of Greenwich = 0h 11m (divide by 15). So Betelgeuse was on the Greenwich meridian 11 minutes before it reached the St.Andrews meridian. i.e. at 20h59m.

For a more detailed discussion of Sidereal Time and related topics, see Chapter 2 of USNO Circular No.179.